Maximum,minimum The maximum value M of $3^x + 5^x – 9^x + 15^x –25^x$ , as x varies over reals, satisfies – A.3<M<5 B.0<M<2 C.5<M<25 D.0<M<9 Answer B. 0<M<2 Explanation $\begin & M=a+b-a^2+a b-b^2 \quad \frac \geq a b \\ & \mathrm^2+\mathrm^2 \geq 2 \mathrm \\ & -\left(a^2+b^2\right) \leq-2 a b \\ & \mathrm \leq \mathrm+\mathrm-\mathrm \\ & \mathrm<\mathrm-(\mathrm-\mathrm)(\mathrm-1) \quad \min \text \\ & \text 0<\mathrm<2 \\ & \end$ takshzila2023-09-22T11:25:48+05:30August 11, 2023| Share This Story, Choose Your Platform! FacebookXRedditLinkedInWhatsAppTumblrPinterestVkXingEmail About the Author: takshzila Leave A Comment Cancel replyYou must be logged in to post a comment.
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