Ujakar and Keshab attempted to solve a quadratic equation. Ujakar made a mistake in writing down the constant term. He ended up with the roots (4, 3). Keshab made a mistake in writing down the coefficient of x. He got the roots as (3, 2). What will be the exact roots of the original quadratic equation?

A. 6,1

B.-3,-4

C.4,3

D.-4,3

A. 6,1

We know that quadratic equation can be written as $ x^2 -(sum of roots)*x+(product of the roots)=0$

Ujakar ended up with the roots (4, 3) so the equation is $x^2 -(7)*x+(12)=0$ where the constant term is wrong

Keshab got the roots as (3, 2) so the equation is $x^2 -(5)*x+(6)=0$ where the coefficient of x is wrong

So the correct equation is $x^2 -(7)*x+(6)=0$ The roots of above equations are (6,1)