Let us take terms of GP as \(\Rightarrow a, ar, {ar}^{2}\)
then the terms in AP will be \(\Rightarrow ar, {ar}^{2}, a\)
In that case, \({ar}^{2} = \frac{a+ar}{2}\)
\({2ar}^{2}=a+ar\)
on simplifying the quadratic we get r = 1 OR r = -1/2
r can not be 1 as that will make each term of the GP same which will not make it an infinite GP, so we get r = -1/2
⇒ Also given that sum to infinite terms of the GP = 36
\(\frac{a}{1-r}=36\)
plugging r=-1/2 we get
a = 54.
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