f(5 + x) = f(5 – x)
Denoting (5 + x) = y,
we have x = y – 5.
And (5 – x) = 5 – (y – 5) i.e. 10 – y.
Replacing (5 + x) with y and (5 – x) with (10 – y),
f(y) = f(10 – y), for all values of y.
If p be a root of f(x)
⇒ f(p) = 0,
And using the earlier relation, f(10 – p) = 0 i.e. (10 – p) is also a root.
Similarly, if q is another root of f(x). Then (10 – q) is also a root.
Adding all 4 root, p + (10 – p) + q + (10 – q) = 20
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