Q.
England and Australia play a test series until one team wins 5 matches. No match ends in a draw. In how many ways can the series be won?
A. 126
B. 252
C. 144
D. 231
E. 280
B. 252
The minimum number of matches that the series can have is 5 matches. And this case is the easiest. The team winning the series, will win all 5 matches in a row i.e. W W W W W, just 1 way.
If the series ends after 6 matches, the 6th match i.e. the last match will be won by the team winning the series … that is how the series ends. And amongst the first 5 matches, 4 matches will be won by the team winning the series and 1 match will be won by the team losing the series.
{W, W, W, W, L} W
Thus the outcome in the first 5 matches can be in 5C1 ways.
If the series ends after 7 matches, the 7th match i.e. the last match will be won by the team winning the series … that is how the series ends. And amongst the first 6 matches, 4 matches will be won by the team winning the series and 2 matches will be won by the team losing the series.
{W, W, W, W, L, L} W
Thus the outcome in the first 6 matches can be in 6C2 ways.
Proceeding the same way, we reach ….
If the series ends after 9 matches, the 9th match i.e. the last match will be won by the team winning the series … that is how the series ends. And amongst the first 8 matches, 4 matches will be won by the team winning the series and 4 matches will be won by the team losing the series.
{W, W, W, W, L, L, L, L} W
Thus the outcome in the first 8 matches can be in 8C4 ways.
And one should realise that this is the longest that the series will play out i.e. by the 9th match, it is necessary that one of the teams wins 5 matches … it is not possible that each team would have won just a maximum of 4 matches.
And not to forget that the winning team could be either England or Australia.
Thus, answer = \(2 \times \left(1 \;+\; ^5C_1 \;+\; ^6C_2 \;+\; ^7C_3 \;+\; ^8C_4\right)\)
= 2 × (1 + 5 + 15 + 35 + 70) = 252
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